Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
Suppose the average weight of 9 persons is 50 kg. The average weight of the first 5 persons is 45 kg, whereas the average weight of the last 5 persons is 55 kg. Then the weight of the 5th person will be
Correct
Ans. (c)
Given:
- The average weight of 9 persons is 50 kg.
- The average weight of the first 5 persons is 45 kg.
- The average weight of the last 5 persons is 55 kg.
Therefore, Total weight of all 9 persons = 50 × 9 = 450 kg
Total weight of first 5 persons = 45 × 5 = 225 kg
Total weight of last 5 persons = 55 × 5 = 275 kg
5th person has been included in first 5 persons as well as last 5 persons.
Hence, the weight of the 5th person = (275 + 225) – 450 = 50 kg.
Incorrect
Ans. (c)
Given:
- The average weight of 9 persons is 50 kg.
- The average weight of the first 5 persons is 45 kg.
- The average weight of the last 5 persons is 55 kg.
Therefore, Total weight of all 9 persons = 50 × 9 = 450 kg
Total weight of first 5 persons = 45 × 5 = 225 kg
Total weight of last 5 persons = 55 × 5 = 275 kg
5th person has been included in first 5 persons as well as last 5 persons.
Hence, the weight of the 5th person = (275 + 225) – 450 = 50 kg.
-
Question 2 of 5
2. Question
P = (40% of A) + (65% of B) and Q = (50% of A) + (50% of B), where A is greater than B.
In this context, which of the following statements is correct?
Correct
Ans. (d)
Given,
P = (40% of A) + (65% of B)
Q = (50% of A) + (50% of B)
where A > B
P – Q = (40% of A) + (65% of B) – (50% of A) – (50% of B)
= (15% of B) – (10% of A)
Let’s consider different scenarios where calculations can be done easily. Use multiples of 10 in such cases as percentage is given in the formula
Let B=100 & A=110 (difference as 10)
P – Q = (15% of B) – (10% of A) =
=[(15/100)*100 ] – [(10/100)* 110]
=15-11 = 4
Therefore P>Q
Let B=100 & A=150 (difference as 50)
P – Q = (15% of B) – (10% of A)
= 15-15 =0
Therefore P=Q
Let B=100 & A=200 (Difference as 100)
P – Q = (15% of B) – (10% of A)
= 15 – 20 = -5
Therefore P<Q
Hence nothing can be said with certainty
Incorrect
Ans. (d)
Given,
P = (40% of A) + (65% of B)
Q = (50% of A) + (50% of B)
where A > B
P – Q = (40% of A) + (65% of B) – (50% of A) – (50% of B)
= (15% of B) – (10% of A)
Let’s consider different scenarios where calculations can be done easily. Use multiples of 10 in such cases as percentage is given in the formula
Let B=100 & A=110 (difference as 10)
P – Q = (15% of B) – (10% of A) =
=[(15/100)*100 ] – [(10/100)* 110]
=15-11 = 4
Therefore P>Q
Let B=100 & A=150 (difference as 50)
P – Q = (15% of B) – (10% of A)
= 15-15 =0
Therefore P=Q
Let B=100 & A=200 (Difference as 100)
P – Q = (15% of B) – (10% of A)
= 15 – 20 = -5
Therefore P<Q
Hence nothing can be said with certainty
-
Question 3 of 5
3. Question
A watch loses 2 minutes in every 24 hours while another watch gains 2 minutes, in 24 hours. At a particular instant, the two watches showed an identical time. Which of the following statements is correct if 24- hour clock is
Correct
Ans. (d)
Given:
A Watch loses 2 minutes in every 24 hours.
Another watch gains 2 minutes in every 24 hours.
Hence, after day 1 the time difference between 2 watches (after 24 hours)= 4 minutes
Also, following the same pattern, difference keeps increasing by 4minutes every day.
Meaning After 1 day = 4 minutes difference, After 2 days = 8 minutes …. This is in AP
4,8,12,16,…
Therefore, clocks can show the same time only when the difference increases to 24hours.
We need to find after how many days difference increases to 24 hours
Let us consider each option:
- 30 days = (30 * 4) = 120 min = (120/60) =2hrs
- 90 days = (90*4)= 360min= (360/60)=6hrs
[ This shows it requires 360 days i.e ( 90days * 4 )= (6hours *4) ]
- 120 days = (120*4) = 480 min = ( 480/60) = 8hrs
Therefore , Solution is D
Incorrect
Ans. (d)
Given:
A Watch loses 2 minutes in every 24 hours.
Another watch gains 2 minutes in every 24 hours.
Hence, after day 1 the time difference between 2 watches (after 24 hours)= 4 minutes
Also, following the same pattern, difference keeps increasing by 4minutes every day.
Meaning After 1 day = 4 minutes difference, After 2 days = 8 minutes …. This is in AP
4,8,12,16,…
Therefore, clocks can show the same time only when the difference increases to 24hours.
We need to find after how many days difference increases to 24 hours
Let us consider each option:
- 30 days = (30 * 4) = 120 min = (120/60) =2hrs
- 90 days = (90*4)= 360min= (360/60)=6hrs
[ This shows it requires 360 days i.e ( 90days * 4 )= (6hours *4) ]
- 120 days = (120*4) = 480 min = ( 480/60) = 8hrs
Therefore , Solution is D
-
Question 4 of 5
4. Question
In a city, 12% of households earn less than Rs. 30,000 per year, 6% households earn more than Rs. 2,00,000 per year, 22% households earn more than Rs. 1,00,000 per year and 990 households earn between Rs. 30,000 and Rs. 1,00,000 per year. How many households earn between Rs. 1,00,000 and Rs. 2,00,000 per year?
Correct
Ans. (b)
Given:
Let total Households be X
Households that earn less than Rs. 30,000 per year = 12%
Households that earn more than Rs 1,00,000 per year = 22%
Households that earn more than Rs 2,00,000 per year = 6%
Hence, households that earn between Rs 1,00,000 and Rs 2,00,000 per year = 22 – 6 = 16%
Households that earn between Rs 30,000 and Rs 1,00,000 per year = 100 – (22 + 12) = 66% = 990
= (66/100)*X = 990
X = (990*100)/66
X = 1500
Therefore, Households that earn between Rs 1,00,000 and Rs 2,00,000 per year = 16% =
(16/100) × 1500 = 240
Incorrect
Ans. (b)
Given:
Let total Households be X
Households that earn less than Rs. 30,000 per year = 12%
Households that earn more than Rs 1,00,000 per year = 22%
Households that earn more than Rs 2,00,000 per year = 6%
Hence, households that earn between Rs 1,00,000 and Rs 2,00,000 per year = 22 – 6 = 16%
Households that earn between Rs 30,000 and Rs 1,00,000 per year = 100 – (22 + 12) = 66% = 990
= (66/100)*X = 990
X = (990*100)/66
X = 1500
Therefore, Households that earn between Rs 1,00,000 and Rs 2,00,000 per year = 16% =
(16/100) × 1500 = 240
-
Question 5 of 5
5. Question
A clock strikes once at 1 o’clock, twice at 2 o’clock and thrice at 3 o’clock, and so on. If it takes 12 seconds to strike at 5 o’clock, what is the time taken by it to strike at 10 o’clock?
Correct
Ans. (b)
1 ‘o’ Clock = 1-time strike
2 ‘o’ Clock = 2 times strike
3 ‘o’ Clock = 3 times strike
4 ‘o’ Clock = 4 times strike
5 ‘o’ Clock = 5 times strike
10 ‘o’ Clock = 10 times strike
To strike for 5 times at 5’0’clock , it takes 12 seconds
To Strike for 10time at 10 ‘o’ clock it takes 12*2 = 24 Seconds
Incorrect
Ans. (b)
1 ‘o’ Clock = 1-time strike
2 ‘o’ Clock = 2 times strike
3 ‘o’ Clock = 3 times strike
4 ‘o’ Clock = 4 times strike
5 ‘o’ Clock = 5 times strike
10 ‘o’ Clock = 10 times strike
To strike for 5 times at 5’0’clock , it takes 12 seconds
To Strike for 10time at 10 ‘o’ clock it takes 12*2 = 24 Seconds
